Answer 1

There are some formulae and sample code (JavaScript) for this here: Movable Type Scripts. Look for 'Destination point given distance and bearing from start point'.

Here's an excerpt of the JavaScript from the site:

var lat2 = Math.asin( Math.sin(lat1)*Math.cos(d/R) + 
                      Math.cos(lat1)*Math.sin(d/R)*Math.cos(brng) );
var lon2 = lon1 + Math.atan2(Math.sin(brng)*Math.sin(d/R)*Math.cos(lat1), 
                             Math.cos(d/R)-Math.sin(lat1)*Math.sin(lat2));

In the above code, d is the distance, brng is the bearing in degrees, and R is the Earth's radius.

Porting this to Java should be trivial.

Answered by: Roland776 | Posted: 26-02-2022

Answer 2

This is called the "first geodesic" (or sometimes "principal geodesic") problem, which will probably help you in finding an algorithm on Google if you need to implement this yourself.

Answered by: Ted769 | Posted: 26-02-2022

Answer 3

Implement this yourself for now, but do expect this function to show up at some point, so code accordingly - create your own function, add a few unit tests.

In the future add the following to you function:

def myFunc(args):
  res = # compute stuff
  #if(debug):
    res2 = # make api call
    assert(res = res2)
  return res

And some time later:

def myFunc(args):
  return # make api call

And some time later remove the function altogether.

Answered by: Rafael808 | Posted: 26-02-2022

Answer 4

Here is the reverse of it:

SphericalUtil.computeOffsetOrigin(loc1, dist, angle);

It also has the distanceBetween function:

SphericalUtil.computeDistanceBetween(...);

Lib:

SphericalUtil

Answered by: Aida338 | Posted: 26-02-2022

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