Sending a serialized object from Android to a servlet using HTTP client

I have tried to create a android application that sends a serialzed object from the phone to a servlet the contents of the object is the input from the user which i will store in a database using hibernate. I believe the problem is around the serializing and deserializing of the object the code is below. If anyone could help i would very greatful.

p.s the class User implements the serializable interface


    public class Adduser extends Activity implements OnClickListener {

 EditText uname;
 EditText password;
 EditText rating;
 EditText date;
 Button add;
 User user;

    public void onCreate(Bundle savedInstanceState) {

        uname = (EditText) findViewById(;
        password = (EditText) findViewById(;
        rating = (EditText) findViewById(;
        date = (EditText) findViewById(;
        add = (Button) findViewById(;

        user = new User();



 public void onClick(View v) {


  HttpClient httpClient = new DefaultHttpClient();
  ObjectOutput out;

    String url = "MY URL goes here";

    HttpPost post = new HttpPost(url);

    //Serialisation of object
    ByteArrayOutputStream bos = new ByteArrayOutputStream() ;
       out = new ObjectOutputStream(bos) ;

       //puts bytes into object which is the body of the http request
       post.setHeader(new BasicHeader("Content-Length", "" + bos.toByteArray().length));

       ByteArrayEntity barr = new ByteArrayEntity(bos.toByteArray()); 
       //sets the body of the request 

       //executes request and returns a response
       HttpResponse response = httpClient.execute(post); 

  } catch (IOException e) {
        Log.e( "ouch", "!!! IOException " + e.getMessage() );



Server side

    public class Adduser extends HttpServlet {

 //logger for properties file
 //private static Logger logger = Logger.getLogger(Adduser.class);

 public void doPost (HttpServletRequest request, HttpServletResponse response) throws ServletException {
  //logger.warn("this is a sample log message.");

  String usern = null;
  String password = null;
  String rating = null;
  String date = null;

  InputStream in;
  try {
   //gets http content body byte array should be on the stream
   in = request.getInputStream();

   //int bytesToRead;
   //bytesToRead =  Integer.parseInt(request.getHeader("Content-Length"));

   //reads inputream contents into bytearray
   int bytesRead=0;
   int bytesToRead=1024;
   byte[] input = new byte[bytesToRead];
   while (bytesRead < bytesToRead) {
     int result =, bytesRead, bytesToRead - bytesRead);
     if (result == -1) break;
     bytesRead += result;

   //passes byte array is passed into objectinput stream 
   ObjectInputStream inn = new ObjectInputStream(new ByteArrayInputStream(input));
   User users = null;
   try {
    //object is read into user object and cast
    users = (User)inn.readObject();
   } catch (ClassNotFoundException e1) {
    // TODO Auto-generated catch block


   //contents of object is put into variables to be passed into database
   usern = users.getusername();
   password = users.getpassword();
   rating = users.getrating();
   date = users.getdate();

  } catch (IOException e2) {
   // TODO Auto-generated catch block

  Session session = null;

   SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory(); 
   session = sessionFactory.openSession();
          //Create new instance of Contact and set 
   Transaction tx = session.beginTransaction();

      Userr user = new Userr();

  }catch(Exception e){
        // Actual contact insertion will happen at this step





Asked by: Adelaide572 | Posted: 20-01-2022

Answer 1

As suggested, use XML or JSON. You can get XStream patched for Android from this blog in order to serialize your objects to XML.

Answered by: Jack311 | Posted: 21-02-2022

Answer 2

Don't use serialization between architectures. Use JSON, XML, or something else that is architecture-neutral.

Answered by: Audrey441 | Posted: 21-02-2022

Answer 3

I second the suggestion of XStream. It is a very nice and easy API. I don't like the Serialization formats XML or JSON though because they are text based. For a more compact serialization format, try ProtoBuf from Google.

Answered by: Wilson118 | Posted: 21-02-2022

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